Chapter 5 - Periodic Classification of Elements Page no - 81
Solution 1
Only one triad of Dobereiner's triads exists in the columns of
Newland's octaves. The triad formed by the elements Li, Na, and K of
Dobereiner's triads also occurred in the columns of Newlands' octaves.
Concept Comprehension: Recall the Dobereiner's triads:
Li, Na and K
Ca, Sr and Ba
Cl, Br and I
Concept Comprehension: Recall the Dobereiner's triads:
Li, Na and K
Ca, Sr and Ba
Cl, Br and I
Solution 2
Limitation of Dobereiner's classification:
All known elements could not be classified into groups of triads on the basis of their properties.
All known elements could not be classified into groups of triads on the basis of their properties.
Concept Comprehension: Recall
that Dobereiner could only classify 3 triads successfully
Solution 3
Limitations of Newland's law of octaves:
(i) It was not applicable throughout the arrangements. It was applicable up to calcium only.
(ii) Those elements that were discovered after Newland's octaves did not find a place in Newlands table.
(iii) The position of cobalt and nickel in the group of the elements containing F and Cl of different properties could not be explained.
(iv) Placing of iron far away from cobalt and nickel, which have similar properties as iron, could also not be explained.
Concept Comprehension: The students should remember the demerits of Dobereiner's, Newland's as well as Mendeleev's classification.
(i) It was not applicable throughout the arrangements. It was applicable up to calcium only.
(ii) Those elements that were discovered after Newland's octaves did not find a place in Newlands table.
(iii) The position of cobalt and nickel in the group of the elements containing F and Cl of different properties could not be explained.
(iv) Placing of iron far away from cobalt and nickel, which have similar properties as iron, could also not be explained.
Concept Comprehension: The students should remember the demerits of Dobereiner's, Newland's as well as Mendeleev's classification.
Chapter 5 -
Periodic Classification of Elements Page no - 85
Solution 1
K is in group 1. Therefore, the oxide will be K2O.
C is in group 4. Therefore, the oxide will be CO2.
Al is in group 3. Therefore, the oxide will be Al2O3.
Si is in group 4. Therefore, the oxide will be SiO2.
Ba is in group 2. Therefore, the oxide will be BaO.
C is in group 4. Therefore, the oxide will be CO2.
Al is in group 3. Therefore, the oxide will be Al2O3.
Si is in group 4. Therefore, the oxide will be SiO2.
Ba is in group 2. Therefore, the oxide will be BaO.
Concept comprehension: Remember
that while writing the formula we cross multiply the valency of the two
elements in order to balance the charges. The students should remember that the
valency of oxygen is 2 and the valency of other elements can be calculated from
their group number.
Solution 2
Scandium and germanium
Concept
comprehension: Recall
that Mendeleev was able to predict the properties of 3 unknown elements which
he had named as eka-boron, eka-aluminium and eka-silicon.
Eka-boron was later named as scandium, eka-aluminium as gallium and eka-silicon as germanium
Eka-boron was later named as scandium, eka-aluminium as gallium and eka-silicon as germanium
Solution 3
Mendeleev's periodic table was based on the
observation that the properties of elements are a periodic function of their
atomic masses. This means that if elements are arranged in the increasing order
of their atomic masses, then their properties get repeated after regular
intervals.
Concept comprehension: The
students should remember that Mendeleev had studied the properties of oxides
and hydrides of the known elements and observed that properties of the elements
orderly recur in a cyclic fashion. He classified the elements on the basis of
their physical and chemical properties in the increasing order of the atomic masses,
in the form of a table.
Solution 4
Noble gases are inert elements. Their
properties are different from all the other elements. Therefore, the noble
gases are placed in a separate group.
Concept comprehension: Recall
that the outermost/valence shell of noble gases is completely filled and
therefore they show chemical inertness.
Chapter 5 - Periodic Classification of Elements Page no - 90
Solution 1
Modern periodic table is based on atomic
numbers whereas Mendeleev's periodic table was based on atomic masses. So,
properties of elements could be explained with more precision when elements
were arranged on the basis of increasing atomic number
For example:
The position of isotopes is taken care of when the elements are arranged in the ascending order of their atomic numbers as they have the same atomic number they do not need to be given separate slots.
Modern Periodic table can justify the position of hydrogen in group 1 as it has one valence electron like other elements of the group.
The anomaly regarding few elements such as tellurium (Te), iodine (I) was solved in Modern table. If arranged in increasing order of their atomic numbers, (Te is 52 and I is 53.) Te will naturally come before I.
For example:
The position of isotopes is taken care of when the elements are arranged in the ascending order of their atomic numbers as they have the same atomic number they do not need to be given separate slots.
Modern Periodic table can justify the position of hydrogen in group 1 as it has one valence electron like other elements of the group.
The anomaly regarding few elements such as tellurium (Te), iodine (I) was solved in Modern table. If arranged in increasing order of their atomic numbers, (Te is 52 and I is 53.) Te will naturally come before I.
Concept comprehension: Recall
that atomic number being a more fundamental property than atomic mass could
explain periodic properties in a better manner.
Solution 2
Calcium (Ca) and Strontium (Sr) are expected to
show chemical reactions similar to magnesium (Mg). This is because the number
of valence electrons (2) is same in all these three elements. And since
chemical properties are due to valence electrons, they show same chemical
reactions.
Concept Comprehension: The
students should remember that elements belonging to same group have same number
of valence electrons and hence similar chemical properties.
Solution 3
(a) Lithium (Li), sodium (Na), and potassium (K) have a single
electron in their outermost shells.
(b) Magnesium (Mg) and calcium (Ca) have two electrons in their outermost shells.
(c) Neon (Ne), argon (Ar), and xenon (Xe) have filled outermost shells.
Concept Comprehension: Recall that elements of group I have 1 valence electron, group II have 2 valence electrons while group XVIII have completely filled valence shell.
(b) Magnesium (Mg) and calcium (Ca) have two electrons in their outermost shells.
(c) Neon (Ne), argon (Ar), and xenon (Xe) have filled outermost shells.
Concept Comprehension: Recall that elements of group I have 1 valence electron, group II have 2 valence electrons while group XVIII have completely filled valence shell.
Solution 4
(a) Yes. The atoms of all the three elements lithium, sodium,
and potassium have one electron in their outermost shell.
(b) Both helium (He) and neon (Ne) have filled outermost shells. Helium has a duplet in its K shell, while neon has an octet in its L shell.
Concept Comprehension: The students must learn the names of first 20 elements of the modern periodic table along with their atomic number.
(b) Both helium (He) and neon (Ne) have filled outermost shells. Helium has a duplet in its K shell, while neon has an octet in its L shell.
Concept Comprehension: The students must learn the names of first 20 elements of the modern periodic table along with their atomic number.
Solution 5
Among the first ten elements, lithium
(Li) and beryllium (Be) are metals.
Concept Comprehension: The key to answering this question lies in fact that metals are present ususally on the left hand side of the Modern periodic table whereas non-metals are present on the right hand side of the Modern Periodic Table.
Concept Comprehension: The key to answering this question lies in fact that metals are present ususally on the left hand side of the Modern periodic table whereas non-metals are present on the right hand side of the Modern Periodic Table.
Solution 6
Galium (Ga)
Concept Comprehension: The key to answering this question lies in fact that metals are present ususally on the left hand side of the Modern periodic table whereas non-metals are present on the right hand side of the Modern Periodic Table. Also, remember that as we move down a group, metallic character increases.
Concept Comprehension: The key to answering this question lies in fact that metals are present ususally on the left hand side of the Modern periodic table whereas non-metals are present on the right hand side of the Modern Periodic Table. Also, remember that as we move down a group, metallic character increases.
Chapter 5 -
Periodic Classification of Elements Page no - 91
Solution 1
(c) The atoms lose their electrons more
easily.
Concept Comprehension: The students should remember that on moving from left to right across the periods of the periodic table, the non-metallic character increases. Hence, the tendency to lose electrons decreases.
Concept Comprehension: The students should remember that on moving from left to right across the periods of the periodic table, the non-metallic character increases. Hence, the tendency to lose electrons decreases.
Solution 2
(b) Mg
X would most likely be in the same group of the Periodic Table as magnesium (Mg).
Concept Comprehension: Recall that valency of Chlorine is 1, therefore we can deduce from the formula XCl2 that the valency of X is 2. Since valency of magnesium is also 2, thus X and Mg belong to same group.
X would most likely be in the same group of the Periodic Table as magnesium (Mg).
Concept Comprehension: Recall that valency of Chlorine is 1, therefore we can deduce from the formula XCl2 that the valency of X is 2. Since valency of magnesium is also 2, thus X and Mg belong to same group.
Solution 3
(a) Neon has two shells, both of which are
completely filled with electrons (2 electrons in
K shell and 8 electrons in L shell).
(b) Magnesium has the electronic configuration 2, 8, 2.
(c) Silicon has a total of three shells, with four electrons in its valence shell (2 electrons in K shell, 8 electrons in L shell and 4 electrons in M shell).
(d) Boron has a total of two shells, with three electrons in its valence shell (2 electrons in K shell and 3 electrons in L shell).
(e) Carbon has twice as many electrons in its second shell as in its first shell (2 electrons in K shell and 4 electrons in L shell).
K shell and 8 electrons in L shell).
(b) Magnesium has the electronic configuration 2, 8, 2.
(c) Silicon has a total of three shells, with four electrons in its valence shell (2 electrons in K shell, 8 electrons in L shell and 4 electrons in M shell).
(d) Boron has a total of two shells, with three electrons in its valence shell (2 electrons in K shell and 3 electrons in L shell).
(e) Carbon has twice as many electrons in its second shell as in its first shell (2 electrons in K shell and 4 electrons in L shell).
Concept
Comprehension: The students must learn the names
of first 20 elements of the Modern Periodic Table along with their atomic
number. The students should also be able to recall the Bohr Bury's rules for
distribution of electrons.
Solution 4
(a) All the elements in the same column as boron have the same
number of valence electrons (3). Hence, they all have valency equal to 3.
(b) All the elements in the same column as fluorine have the same number of valence electrons (7). Hence, they all have valency equal to 1.
Concept Comprehension: Recall that elements of same group have same number of valence electrons and hence the same valency. (For group I, II and XIII the valency is equal to the number of valence electrons while for group XIV to XVII the valency is equal to 8 - number of valence electrons.)
(b) All the elements in the same column as fluorine have the same number of valence electrons (7). Hence, they all have valency equal to 1.
Concept Comprehension: Recall that elements of same group have same number of valence electrons and hence the same valency. (For group I, II and XIII the valency is equal to the number of valence electrons while for group XIV to XVII the valency is equal to 8 - number of valence electrons.)
Solution 5
The atomic number of this element is 17.
(b) It would be chemically similar to F (9) with configuration as 2, 7.
Concept Comprehension: The key to answering this question lies in fact that elements with same number of valence electrons belong to the same group and have similar chemical properties.
(b) It would be chemically similar to F (9) with configuration as 2, 7.
Concept Comprehension: The key to answering this question lies in fact that elements with same number of valence electrons belong to the same group and have similar chemical properties.
Chapter 5 -
Periodic Classification of Elements Page no - 92
Solution 1
(a) A is a non-metal.
(b) C is more reactive than A
(c) C will be smaller in size than B
(d) A will form an anion
Concept comprehension: The students should understand and remember the periodic tends as they are often asked in exams.
Solution 2
Element
K L M
Nitrogen
2 5
Phosphorus
2 8 5
Nitrogen
is more electronegative than phosphorus. On moving down a group, the number of
shell increases. Therefore, the valence electrons move away from the nucleus
and the effective nuclear charge decreases. This causes the decrease in the
tendency to attract electron and hence electronegativity decreases.
Concept comprehension: Recall that electronegativity of an element depends on its ability to gain electrons to complete their octet configuration.
Concept comprehension: Recall that electronegativity of an element depends on its ability to gain electrons to complete their octet configuration.
Solution 3
In the Modern Periodic Table, atoms with similar electronic
configurations are placed in the same group. In a group, the number of valence
electrons remains the same. Elements across a period show an increase in the
number of valence electrons in the same shell.
Concept comprehension: The students should remember that from the group of an element we can find out the number of valence electrons while from the period we can deduce the number of shells present in atom
Concept comprehension: The students should remember that from the group of an element we can find out the number of valence electrons while from the period we can deduce the number of shells present in atom
Solution 4
The elements with atomic number 12 and 38 have same chemical
properties as that of calcium. This is because both of them have same number of
valence electrons (2) as calcium.
Concept comprehension: While answering this kind of a question the students should write the electronic configuration of all elements given in the question.
Atomic number
K, L, M, N, O
12 2,8,2
19 2,8,8,1
21 2,8,8,3
38 2,8,18,8,2
Since elements with same number of valence electron shave similar properties, the elements which have 2 valence electrons will have physical and chemical properties resembling that of calcium
Concept comprehension: While answering this kind of a question the students should write the electronic configuration of all elements given in the question.
Atomic number
K, L, M, N, O
12 2,8,2
19 2,8,8,1
21 2,8,8,3
38 2,8,18,8,2
Since elements with same number of valence electron shave similar properties, the elements which have 2 valence electrons will have physical and chemical properties resembling that of calcium
Solution 5
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Mendeleev's Periodic Table
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Modern periodic Table
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1.Elements
are arranged in the increasing order of their atomic masses.
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1.
Elements are arranged in the increasing order of their atomic numbers.
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2.There
are a total of 7 groups (columns) and 6 periods (rows).
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2.There
are a total of 18 groups (columns) and 7 periods (rows).
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3.
The position of hydrogen could not be explained.
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3.
Hydrogen is placed above alkali metals as it has one valence electron.
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4.No
distinguishing positions for metals and non-metals was assigned.
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4.Metals
are present at the left hand side of the periodic table whereas non-metals
are present at the right hand side.
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Concept comprehension: The students should be able to clearly list the differences between Mendeleev's and modern classification as it is a favourite with examiners.
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